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X(2), X(523), X(524), X(620), X(671), X(690), X(5466) X(5466) = E1 = (b^2  c^2) / (b^2 + c^2  2a^2) : : , barycentric quotient of X(523) and X(524) 

K239 and K240 generates a pencil of cubics which contains only one other pK. It is K241 with pole X(523) and pivot X(5466). 
